[TASK] Solved Day 15

input/day15.txt

@@ -0,0 +1 @@
+17,1,3,16,19,0

input/day15_example.txt

@@ -0,0 +1 @@
+0,3,6

src/day14.rs

@@ -31,12 +31,13 @@ fn solve_part1(lines: &Vec<String>) -> u64 {
 
 fn solve_part2(lines: &Vec<String>) -> u64 {
 
-    /// Idea for performance optimalization: use a Vec containing the "root" memory position, and
+    /*
-    /// the mask of the floats used to write to that position.
+    Idea for performance optimalization: use a Vec containing the "root" memory position, and
-    /// Whenever something is written, check (using bit operations) if a collision between existing
+    the mask of the floats used to write to that position.
-    /// memory positions is possible. If that is the case, modify the old (existing) entry by
+    Whenever something is written, check (using bit operations) if a collision between existing
-    /// removing all overlapping entries in the float mask.
+    memory positions is possible. If that is the case, modify the old (existing) entry by
-    ///
+     removing all overlapping entries in the float mask.
+     */
 
     let mut mem: HashMap<u64, u64> = HashMap::new();
     let mut mask = MemoryBitMask { ones_mask: 0, float_masks: Vec::new() };
@@ -85,9 +86,7 @@ impl BitMask {
 
 
     fn apply(&self, x: u64) -> u64 {
-
         return (x & self.zeros_mask) | self.ones_mask;
-
     }
 }
 

src/day15.rs

@@ -0,0 +1,41 @@
+use super::util;
+
+pub fn solve() {
+    let lines = util::read_file("input/day15.txt");
+    let starting_numbers = lines[0].split(",").map(|s| s.parse::<usize>().unwrap()).collect::<Vec<_>>();
+
+    let part1 = play_until(2020, &starting_numbers);
+    println!("Day X Part 1: {}", part1);
+
+
+    let part2 = play_until(30_000_000, &starting_numbers);
+    println!("Day X Part 2: {}", part2);
+}
+
+fn play_until(max_turn: usize, starting_numbers: &Vec<usize>) -> usize {
+
+    // Because numbers can never be bigger than the number of turns, this works:
+    let mut last_occurrence = vec!{0usize; max_turn};
+
+    // Note: we ignore the last number here; it will be the "previous_number" later.
+    for i in 0..(starting_numbers.len() - 1) {
+        let n = starting_numbers[i];
+        last_occurrence[n] = i + 1;
+    }
+
+    let mut previous_number = starting_numbers[starting_numbers.len() - 1];
+    for turn in starting_numbers.len()..max_turn {
+
+        let prev_occurrence = last_occurrence[previous_number];
+        last_occurrence[previous_number] = turn;
+        if prev_occurrence == 0 {
+            previous_number = 0;
+        } else {
+            previous_number = turn - prev_occurrence;
+        }
+        println!("Turn {}: {}", turn + 1, previous_number);
+    }
+
+    return previous_number;
+
+}

src/main.rs

@@ -16,9 +16,10 @@ mod day11;
 mod day12;
 mod day13;
 mod day14;
+mod day15;
 
-const MAX_DAY: u8 = 14;
+const MAX_DAY: u8 = 15;
-const BENCHMARK_AMOUNT: u32 = 1000;
+const BENCHMARK_AMOUNT: u32 = 100;
 
 fn solve(day: u8) {
     match day {
@@ -36,6 +37,7 @@ fn solve(day: u8) {
         12 => day12::solve(),
         13 => day13::solve(),
         14 => day14::solve(),
+        15 => day15::solve(),
         _ => println!("This day is not yet implemented")
     }
 }